On Sat, 27 Feb 2021 15:20:57 -0800 (PST), "
wrote:
Don Pearce wrote:
================
Nothing to do with the frequency of the wave or its harmonics. Each
ringing event is separate and is triggered by the broadband energy of
the rising or falling edge.
** Gobbledegook.
Don't be so hasty. I know this is not instantly intuitive, but it is
exactly what happens.
** No it ain't.
The frequency of the ring is determined by
the LC circuit that is being struck by that edge.
** So a linear circuit with a resonance creates a new frequency ?
No.
** You are here claiming it does.
If you do an FFT on an edge,
** Not the situation.
The *square wave* can be band limited to just a few times the ringing frequency.
Only needs ONE harmonic close enough to that frequency to get a damped sine result.
Does not do so with a sine sweep.
If you do a sine sweep you will find the resonant frequency of the ring.
** But not *create* it - the maximum is at the exact same frequency as the input sine.
That is the frequency you will see when you strike it with a
fast rising edge.
** Not the case with a normal, square wave test.
..... Phil
Phil, you need to think. Forget square waves and harmonics for a
moment. You can trigger ringing with a single transient edge. No
repetition or harmonics needed.
d
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