[ShadowTek]

On 2010-02-11, David Nebenzahl wrote:
On 2/10/2010 2:26 PM ShadowTek spake thus:

At my disposal are three 4-ohm speakers and one 16-ohm speakers.
I'm considering wiring the three 4-ohm speakers in series, then
connecting that in parallel to an 16-ohm speaker, which should result
in in overall 8-ohm load.

4-4-4
|_____amp
|
16

Wrong.

The formula for parallel resistance is:

R1 R2
Rt = --------
R1 + R2

yielding ~6.8 ohms in this case. Close, but no cigar.

LMFAO I'd added 4+4+4 in my head and got 16!

I did it right, I just messed up. lol


Is there any danger with having 1 speaker on one side of the parallel,
while having 3 speakers on the other side?

Nope, although don't expect equal power distribution among the various
speakers. But so far as the amp goes, it doesn't care who is where.

Assuming that there would be 16 ohms on *both* sides of the parallel
(like I was originally thinking), the power distribution among the four
4-ohms and the one 16-ohm would be the same, right?

4+4+4+4
|______amp
|
16